M. Berrer - D. Evans

In the past and in this ATP tournament, I supported China against Medi. I even dreamed that Medvedev was not successful in the match against the previous tour's winner, where he won the first set but lost the second. I dreamt that I consoled Medvedev for playing better but losing. Now we see a different scenario: he won against the previous winner in a close match and managed to win the match with a similar situation in the second set, despite a psychological block at the end of the set, as he himself said. But he didn't let the second set slip away this time and took the match with a stumbling opponent. Today, he played against de Minaur, who may not have been considered a clear favorite, but he handled the pressure and crucial moments well, leaving de Minaur to say goodbye. Now we face Rindernknere, who is not better than de Minaur, and I think we have a good coefficient with -3 games advantage. Good luck.

The cosmic coefficient for over seems to end more realistically. The Frenchman's fairy tale should end here just like his stepbrother's. Rinderknech has a nice serve, but Medvedev has an even better return. In the game against Peru - everyone will be grazing on Medvedev's side. Overall, the player is not stable enough in longer points and Rinderknech will only have to try and hit lines where there will be a lot of out of bounds and nets. I am personally expecting an easy win for Peru, unless Medvedev starts pulling muscles again.

Although Medvedev does not quite have control over his emotions, he shines in this tournament. Giving up just one set to Thiem, defeating Fokina and De Minaur shows the Russian's confidence in this tournament. The Frenchman is playing above his abilities, but players of this level, especially servers, do not have such long and exceptional winning streaks, and it will be difficult for him to break through Medvedev's strong defense. We will see how much space Medvedev will give the Frenchman to feel good, but in this match, I believe Medvedev will win and do so in two sets.